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let f(x)= (x-5)/2. Find f^-1
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\( \color{Black}{\Rightarrow y = \Large{x - 5 \over 2} }\) \( \color{Black}{\Rightarrow 2y = x - 5 }\) \( \color{Black}{\Rightarrow 2y + 5 = x }\) Just replace y with x, and x with f^-1(x) \( \color{Black}{\Rightarrow f^{-1}(x) = 2x + 5 }\)
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