Mathematics
8 Online
OpenStudy (anonymous):
what are the solutions of the system? y=x^2-x+2
y=x+5
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OpenStudy (anonymous):
set those two equation equal to each other in y:
OpenStudy (anonymous):
x^2 - x + 2 = x + 5
x^2 - 2x - 3 = 0
can you take it from here?
OpenStudy (anonymous):
x^2 -x+2=x+5 and solve it
OpenStudy (anonymous):
oh dpalnc did the same :)
OpenStudy (anonymous):
i dont think so..
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OpenStudy (anonymous):
all yours @kittu ... :)
OpenStudy (anonymous):
@Mujod122 i didn't get you
@dpaInc :)
OpenStudy (anonymous):
i have no idea how to do this
OpenStudy (anonymous):
oh yeah they don't have real roots
OpenStudy (anonymous):
sorry i should've checked
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OpenStudy (anonymous):
oh no they have real roots
OpenStudy (anonymous):
x^2 - 2x - 3 = 0 and the roots are -1 and +3
OpenStudy (anonymous):
now substitute these two in the equation and find the value of y
OpenStudy (anonymous):
x=3,-1
??
OpenStudy (anonymous):
yeah man.... what is the problem you have then ?
u get two answers for this because it is a quadratic equation
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OpenStudy (anonymous):
idk i got confused thanks
OpenStudy (anonymous):
I can help you if you tell me the part you don't understand :)