Question

solve (1/9)= 27^(3x-5)

Answer 1

-2/3 = 3x-5
5-2/3 = 3x = 4 1/3 or 13/3
x = 13/3 * 1/3 = 13/9.

Answer 2

\[\frac{1}{9} = 3^{-2}\]

and \[27^(3x-5)= 3^{3\times(3x - 5)}\]

equate the powers and solve for x

-2 = 9x - 15

13 = 9x

x = 13/9