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Subtract. Simplify, if possible 6-y/y-7 minus 8y-7/7-y =
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the solution is \[\frac{48}{y-7}+7\]
(1-7y)/(7-y)
I came up with the first answer....why is that??
evaluate the following \[\frac{(7-y)(6-y)-(y-7)(8y-7)}{(y-7)(7-y)}\]
that gives \[\frac{-(y-7)(7y-1)}{(y-7)(7-y)}\]
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last step is to factorise & cancel y-7 from top and bottom to give \[\frac{−(7y−1)}{−(y−7)}\]
And that gives 48/y-7+7 right
yep :D
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