Question

The asymptotes of q(x) = 1/2 csc 2x are

Answer 1

\[q(x)=1/2\sin2x\]
asymptote denominator is zero
\[2\sin 2x=0\]
\[\sin 2x=0\]
\[2x=2.\pi.k,k \epsilon \mathbb{R}\]
\[x=2.\pi.k\]

Answer 2

\[\csc x=1/\sin x\]

Answer 3

so x is
\[(\pm 2\pi,\pm4\pi...)\]