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OpenStudy (anonymous):
What polynomial has roots of -6, -4, and 1 ?
x3 - 9x2 - 22x + 24
x3 - x2 - 26x - 24
x3 + x2 - 26x + 24
x3 + 9x2 + 14x - 24
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OpenStudy (cwrw238):
(x+6)(x+4)(x-1) = 0 has these roots
which will expand to one of your options
OpenStudy (cwrw238):
= (x-1)(x^2 +10+24)
OpenStudy (cwrw238):
that narrows it down to 2nd or 4th (-24)
OpenStudy (cwrw238):
that should be 10x in second parentheses
OpenStudy (cwrw238):
expansion will give -10x +24x - so which ne do you think it is?
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OpenStudy (anonymous):
i think the 3rd one?
OpenStudy (cwrw238):
nope -10x + 24x = +14x
OpenStudy (cwrw238):
check out the one with +14x in it
OpenStudy (cwrw238):
it cant be the 3rd one as it contains +24 - - see above - it must contain -24
OpenStudy (anonymous):
shoot ok let me see
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OpenStudy (anonymous):
the last one right? i didnt even see the 14x haha
OpenStudy (cwrw238):
right - hope you dont mind me 'playing' with you - they like us to guide you through on this site - not just give you the answer
OpenStudy (anonymous):
no i understand i rather understand how to solve it then just get an answer :]
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