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Mathematics
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\[\frac{-4.9(9)+4.9t^2-300}{3-t}=\frac{4.9t^2-344.1}{3-t}\]
Now what? :O
Is it -29.4?
I made a mistake. Find the s(3)and subtract the s(t)
I got -29.4, and thats what I did.
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Yep. that is correct.
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