Question

Please help! What is the solution set for sin(2x)= -square root 3 / 3 ?

Answer 1

2x=5pi/6, 11pi/6, 17pi/6, 23pi/6
x=5pi/12, 11pi/12, 17pi/12, 23pi/12+2npi

Answer 2

So if the interval is x is greater than or equal to 0 and less than 2pi than the set would be 5pi/12, 11pi/12 and 17pi/12 ?

Answer 3

yes if you also include 23pi/12

Answer 4

Ok thanks!