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Solve x2 + 18x - 40 = 0.
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first factor the trinomial it will be of the form (x - a)(x + b) where a and b are constants to find a and b: you need two numbers whose product is -40 and whose sum is + 18
have you had experience of factoring these?
no I don't get it at all
ok the 2 numbers are + 20 and -2 20*-2 = -40 and 20 - 2 = 18 so we have (x + 20)( x - 2) = 0 when 2 items are multiplied together to give zero either one of them must equal zero so either x + 20 = 0 or x - 2 = 0 that gives x = -20 or x = 2 solution is -20, 2
hope this helps
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thanks alot
yw
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