Question

For triangle ABC,angle A=35°angle B=55° and side c=70. find side a

Answer 1

angle C is \(180-55-35=90\) so law of sines tell you
\[\frac{a}{\sin(35)}=\frac{70}{\sin(90)}\]

Answer 2

C=90
A/SIN a=C/SIN c

Answer 3

since
\(\sin(90)=1\) you get
\[a=70\times \sin(35) \] then a calculator