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(x2 + 13x + 40) ÷ (x + 8) show steps please
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does it help to know that \[x^2+13x+40=(x+8)(x+5)\]?
no..could you work it out please?
since the numerator factors as \[(x+8)(x+5)\] then \[\frac{x^2+13x+40}{x+8}=\frac{(x+8)(x+5)}{x+8}= \frac{\cancel{(x+8)}(x+5)}{\cancel{x+8}}=x+5\]
Okay, I have a better understanding now. thanks
yw
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