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solve 16^x=4^3x-6
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\[16^x = 4^{3x - 6}\] rewrite both sides as powers of 4 \[(4^2)^x = 4^{3x - 6}\] then \[4^{2x} = 4^{3x - 6}\] equate the powers and solve 2x = 3x - 6 subtract 3x from both sides -x = -6 divide by -1 x = 6
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