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solve 3^x=5^(x+2)
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Hi babyg8trgrl :) How are you dear?
You have to take log on both sides of the equation.
im doing good i just dont understand this
\[\Large 3^x=5^{x+2}\] \[\Large log(3^x)=log(5^{x+2})\] \[\Large xlog(3)=(x+2)log(5)\] \[\Large x(0.477)=(x+2)(0.7)\] \[\Large 0.477x=0.7x+1.4\] \[\Large 0.477x-0.7x=1.4\] Now can you solve from here if I left it?
would i just slove for x?
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Yes dear.
i got x=-6.278 is that right??
Let me check dear.
Congratulation. You have done it. :D
yay! thank you so much!
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You are ever welcome dear. :p
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