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Mathematics 16 Online
OpenStudy (anonymous):

please help.

OpenStudy (anonymous):

\[20z \over \sqrt{z^13}\]

OpenStudy (cwrw238):

what exactly is the denominator?

OpenStudy (anonymous):

What do you mean?

OpenStudy (cwrw238):

is the square root of z cubed?

OpenStudy (anonymous):

no its to the 13th

OpenStudy (anonymous):

|dw:1338929819612:dw|

OpenStudy (anonymous):

the numerator is 20z

OpenStudy (cwrw238):

= 20z / z^(13/2) = 20 z^(1 - 13/2) = 20 z^(-11/2) or 20 / sqrt(z^11)

OpenStudy (anonymous):

THANK YOU! :) Your awesome @cwrw238 ! :)

OpenStudy (cwrw238):

you r welcome

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