Question

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Answer 1

if we isolate the triangleuse the law of cosine to find P1P2\[\left( P_1 P_2 \right)^2 = r_1^2 + r_2^2 - 2r_1r_2 \cos \theta\]\[P_1 P_2 = \sqrt{r_1^2 + r_2^2 - 2r_1r_2 \cos \theta}\]\[P_1 P_2 = \sqrt{r_1^2 + r_2^2 - 2r_1r_2 \cos \left( \beta_1 - \beta_2\right)}\]