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Use the quadratic equation y = x^2 + 3x – 10. Where does the vertex of the parabola lie? A. below the x-axis B. above the x-axis C. on the x-axis D. on the y-axis
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first coordinate of the vertex is always \(-\frac{b}{2a}\) in your case it is \[-\frac{3}{2}\] to find the second coordinate, replace \(x\) by \(-\frac{3}{2}\) and see what you get
i am fairly sure that the answer will be negative, so it lies below the x - axis
ty
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