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OpenStudy (anonymous):
Trigonometry? what is the smallest value for x where y =sin2x reaches its maximum? explain please
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OpenStudy (anonymous):
sine is biggest when it is 1, and \(\sin(\frac{\pi}{2})=1\) so set \[2x=\frac{\pi}{2}\] and solve for \(x\) in one step
OpenStudy (anonymous):
oh okay thank you
OpenStudy (anonymous):
yw
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