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Solve 4x2 = 20x. Answer x = 4, x = 5 x = 4, x = -5 x = 0, x = 5 x = 0, x = -5
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correct.. is... 4x^2 = 20x
5
cancel off x 4x=20 x=5
also not expression holds for x=0 too
so x=5,x=0
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x = 0, x = 5
4x^2 = 20x 4x^2 - 20x = 0 4x(x-5) = 0 4x = 0 or x-5 = 0 x = 0 or x = 5
note that @jim_thompson5910 used the systematic method for doing sch qns , what i did is also right bt before cancelling the x on both sides i looked at the condition when x=0
ok thanks guys shows me two diffrent ways to do it..
it is adviced u clearly understand our wrking
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