Question

Can someone help me to solve the following equation system.
y² =x+1
x² + y² =13

Answer 1

x=-4 and x=3?

Answer 2

x^2 + (x+1) = 13
x^2 + x -12 = 0

(x+4)(x-3) = 0

x= -4 , x = 3

Answer 3

substitute the first equation y^2 = x + 1 into the second equation

x^2 + x + 1 = 13

now you have a polynomial equation, just re arrange to

x^2 + x + 1-13 = 0

and use the quadratic formula to solve

Answer 4

Thanks guys

Answer 5

then make sure you solve for y