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Mathematics 19 Online
OpenStudy (anonymous):

Rational Expressions and Functions: http://i47.tinypic.com/sbua04.png

OpenStudy (anonymous):

I would start by multiplying both sides of the equation by 3x+9 and see what happens :)

OpenStudy (anonymous):

Thanks, I'll see if that gets me the answer.

Parth (parthkohli):

I have a suggestion here. Shall I spit it out?

OpenStudy (anonymous):

Nah, don't work, it's a fill-in answer. @ParthKohli Sure.

Parth (parthkohli):

Multiply both the numerator and denominator of \(\Large {2 \over x + 3}\).That'll get you two like terms :)

Parth (parthkohli):

Multiply both numerator and denominator by 3*

OpenStudy (anonymous):

okay, bottom is 9, top is 6. Is there another step?

OpenStudy (anonymous):

I do see the nine and nine, like terms.

Parth (parthkohli):

\(\color{Black}{\Rightarrow \Large{1 \over 3x + 9}- {3(2) \over 3(x + 3)} }\)

OpenStudy (anonymous):

I see, but still confusing.

Parth (parthkohli):

I don't find anything confusing here. \(\color{Black}{\Rightarrow \Large {x \over y} = {ax \over ay}}\) This is what I am doing here.

OpenStudy (anonymous):

I know, but this is one of the first units, I'm really, for some reason, having trouble with. Okay, you say, 'Multiply both numerator and denominator by 3*', Okay then what do I do?

Parth (parthkohli):

You'll get two like terms :)

Parth (parthkohli):

First simplify the thing I gave you

OpenStudy (anonymous):

\[1/3x + 9 - 6 / x9\] ^^Don't know how to really format it, but the 6 and 9 is there.

Parth (parthkohli):

No no

OpenStudy (anonymous):

Or am I missing something

Parth (parthkohli):

\(\color{Black}{\Rightarrow 3(x + 3) = 3x + 9 }\)

OpenStudy (anonymous):

okay look, we both are going in circles, but probably my fault, but I see the like terms, but what do I do now? :L lol...

Parth (parthkohli):

just operate on the numerators.

OpenStudy (anonymous):

Nope, couldn't get anything. Okay, I don't want to waste anymore of your precious time, so I'ma ask for a straight up answer? This pellet is just hard for me, point blank.

OpenStudy (anonymous):

or tell me next steps, I don't mind learning it.

Parth (parthkohli):

Wolfram if you want the straight answer.

OpenStudy (anonymous):

lol i just want to learn the steps, but I don't want to waste ur time tutoring me.

Parth (parthkohli):

\(\color{Black}{\Rightarrow \Large {1 \over 3x+ 9} -{6 \over 3x + 9} = 2 }\) \(\color{Black}{\Rightarrow \Large {-5 \over 3x + 9} = 2 }\) Multiply both sides by 3x + 9 \(\color{Black}{\Rightarrow-5 = 2(3x+ 9) }\) \(\color{Black}{\Rightarrow -5 = 6x + 18 }\) \(\color{Black}{\Rightarrow -23 = 6x }\) \(\color{Black}{\Rightarrow x = {-23 \over 6} }\)

OpenStudy (anonymous):

k i was good up till the part with the Multiply both sides by 3x + 9... but Ima let you go, I promise, Im not here just for the answer. Ima learn this stuff, I don't want to be a leecher my whole life. Thanks, bye.

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