A positive integer is divided by a smaller positive integer. The integer part of the quotient is 7 and the remainder is 2. If the sum of the two integers is 42, what are the two integers?

Question

shubhamsrg · Answer

let greater one be x and smaller be y
it says that x = 7y + 2
and x+y =42..
shouldnt it be easy now ?

anonymous · Answer

can you put it into an equation? @shubhamsrg

shubhamsrg · Answer

what ? you mean one single eqn ? just make this subsn : put the value of x from 1st eqn into 2nd one..and see the magic! :D

anonymous · Answer

@shubhamsrg ,only the integer part of the quotient is given........
no problem kyaaa!!!

anonymous · Answer

i dont understand

shubhamsrg · Answer

well if you take that into account then i dont think you can actually come up with 2 eqns.. how will you use this fact..and at this level,,i guess we have to take that as 7 only..hmmn,.

shubhamsrg · Answer

@tbrooks3 see we have this x=7y+2 and x+y =42
from 1st eqn,,2nd becomes => (7y+2) +y =42
will this help ?

anonymous · Answer

yes thanks

anonymous · Answer

i too thought so...
i asked just for clarificaton:)))

shubhamsrg · Answer

glad to help ^_^

shubhamsrg · Answer

@anusha.p lets consider what you're saying,,let the fraction part be f
now we have  x = (7+f)y + 2
and x+y =42
=> 8y + fy = 40
y = 40/(8 +f)
since f lies between 0 and 1,,y thus lies between 5 and 4.444...
thus x lies between 37 and 38.5555...
so you see..hmmn..

anonymous · Answer

@shubhamsrg got u!!!