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2(2c)-6(c-1)=-5(c+3)+11 solve symbolically < or>
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Facts you may need: \(a(b+c)=ab+ac\) \(\{+,\times\}\) has the set of inverse operations \(\{-,\div\}\).
i broke it down to 3c =-10 but dont know if its right or what to do
I think you made an error somewhere. Check your calculations.
ok let me check
cant figure it out
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Sorry! I had made an error myself. You were correct. All you do now is divide by \(3\). I am so sorry.
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