Question

Write the standard equation for the circle center (–6, 7), r = 9. (1 point)
(x – 6)2 + (y + 7)2 = 9
(x – 7)2 + (y + 6)2 = 81
(x + 6)2 + (y – 7)2 = 81
(x + 6)2 + (y – 7)2 = 9

Answer 1

. Write the standard equation for the circle center (–6, –8), that passes through (0, 0). (1 point)
(x – 6)2 + (y – 8)2 = 10
(x – 6)2 + (y – 8)2 = 196
(x + 6)2 + (y + 8)2 = 14
(x + 6)2 + (y + 8)2 = 100

Answer 2

(x-h)^2+(y-k)^2=r^2 where h and k are the coordinates (h,k)
which would give you (x+6)^2+(y-7)^2=81 for the first one..

Answer 3

Get it?

Answer 4

no