Write the standard equation for the circle center (–6, –8), that passes through (0, 0). (1 point)
(x – 6)2 + (y – 8)2 = 10
(x – 6)2 + (y – 8)2 = 196
(x + 6)2 + (y + 8)2 = 14
(x + 6)2 + (y + 8)2 = 100

Question

Write the standard equation for the circle center (–6, –8), that passes through (0, 0).  (1 point)
(x – 6)2 + (y – 8)2 = 10
(x – 6)2 + (y – 8)2 = 196
(x + 6)2 + (y + 8)2 = 14
(x + 6)2 + (y + 8)2 = 100

anonymous · Answer

the standard form for the equation of a circle is: $\large (x-h)^2+(y-k)^2=r^2 $ where (h, k) is the center and r is the radius.

can you tell me what (h, k) is ?