Multiply. (j + 7)(j – 7)
j2 + 14j – 49
j2 – 14j – 49
j2 + 14j – 49
j2 – 49

Question

Multiply. (j + 7)(j – 7)   
j2 + 14j – 49
j2 – 14j – 49
j2 + 14j – 49
j2 – 49

anonymous · Answer

I think it is D am I right???

anonymous · Answer

It's difference of two squares (DOTS) so it is j^2 - 49. Yep, you're right :D

To show this:

j^2 - 7j + 7j - 49

the two 7j's cancel out and you're left with

j^2 - 49

anonymous · Answer

Yay I was right thanks!
can you check this one

Multiply. (2n + 2)(2n – 2)  (1 point)
4n2 – 4
4n2 – 4n – 4
4n2 + 2n – 4
4n2 + 4n – 4

apoorvk · Answer

(a+b)(a-b) = a^2 - b^2     ----> ever heard of this identity?

anonymous · Answer

i think it is b but i am not sure the other one i was sure and had to make sure i was correct but not this one

apoorvk · Answer

Nyet. Not B.

Again, it's in "(a+b)(a-b)" form. here your 'a' would be '2n' and your 'b' would '2'. So whaddya think now?