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OpenStudy (anonymous):
Find the scalar equation of the plane that contains the intersecting lines (x-2)\1=y\2=(z+3)\3 and (x-2)/-3=y\4=(z+3)\2.
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OpenStudy (anonymous):
Normal vector = <1, 2, 3 > x <-3, 4, 2 > = < -8, -11, 10 > (P) : < -8, -11, 10 > . < x - 2, y , z + 3 > -8x -11y + 3z + 46 = 0
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