Question

Find the equation of the circle that satisfies the conditions:
Center at the origin, pass through P(4,-7)

Answer 1

I got \[x^2+y^2=65\]

Answer 2

the radius would be distance formula from point (4,-7) to (0,0)

Answer 3

Yes! You got it!

Answer 4

r^2 = x^2 + y^2 :)

Answer 5

no, h and k are the origin 0,0

Answer 6

@ParthKohli center at origin

Answer 7

4,-7 is the point that the radius hits

Answer 8

Thanks everyone!!!

Answer 9

it's good that you're improving @purplec16 ^_^

Answer 10

huh?

Answer 11

uhoh, it appears that in order to learn math better she might of had to forgotten some english skills :)

Answer 12

lol

Answer 13

lol...