Question

Can anyone help me with college
algebra?

Answer 1

What is the question?

Answer 2

Hello

Answer 3

Hi.

Answer 4

I am trying to find free tutoring help. Would you be willing to help me?

Answer 5

Do you have a specific question? Because whatever question you need help with this site is practically designed for that. So post away and ask for explanation when you don't understand. But if you have a question and I am able to help you I will.

Answer 6

Okay I am working on a problem currently x(x-8)+12=0

Answer 7

I have broken it down to x^2-8x+12=0 and I know I need to use the quad. formula which is x=-b +- square root of b^2 -4ac divided by 2a

Answer 8

or you can factor it does the instructions say to solve using the quadratic formula

Answer 9

No bt ut

Answer 10

(x-2)(x-6)=0

Answer 11

No but I don't know how to factor it I suppose

Answer 12

You can use various methods.. the trial and error or you can multiply the coefficient of the first term by the constant in the last term which is 1*-12 which is -12 and look for two factors of 12 (1,2,3,4,6,12) that give you -8 and looks like our factors are -2 and -6.

Answer 13

Thus x^2-2x-6x+12=0
x(x-2)-6(x-2)=0
(x-6)(x-2)=0

Answer 14

Wow thanks!

Answer 15

You are surely welcome!

Answer 16

So the answer is then 2,6

Answer 17

Yes :). x=-2 and x=6.

Answer 18

thank you

Answer 19

No problemo! If you have any other questions you can close this one and ask it in the question window at the top because posting multiple questions in one window tends to slow down your computer.

Answer 20

One other question

Answer 21

why are you multiplying one by -12 and not 12