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If sin θ = 2/x in the first quadrant, what is the expression for the hypotenuse of the right triangle? What about cos θ, sec θ, and cot θ?
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Sin = opp/hyp Right? So what's your hypotenuse here? |dw:1339045390791:dw| Sorry meant 2 not 12. Can you solve the rest?
sec= 1/cos and cot=1/tan
|dw:1339004234662:dw|
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