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Mathematics 8 Online
OpenStudy (anonymous):

what is the derivative of lnsinx

OpenStudy (lgbasallote):

ln (sin x) we know that the derivative of ln u = 1/u

OpenStudy (anonymous):

derivative of \[\ln x= 1/x\] But then we have another function inside ln so chain rule my friend

OpenStudy (lgbasallote):

therefore derivative of ln (sin x) = 1/sin x but wait! you still have to take the derivative of sin x

OpenStudy (lgbasallote):

so go and take the derivative of sin x what do you have??

OpenStudy (anonymous):

Then multiply it to 1/sinx

OpenStudy (lgbasallote):

^that

OpenStudy (lgbasallote):

do you get it @demisew12 ??

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