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Mathematics 13 Online
OpenStudy (anonymous):

Factor completely: 14x2 + 47x + 15 (14x + 3)(x + 5) (14x + 5)(x + 3) (2x + 3)(7x + 5) (2x + 5)(7x + 3)

OpenStudy (anonymous):

since this is multiple choice, just check the Inside and Outside products' sum that will give you 47 ... and last term product of 15...

OpenStudy (anonymous):

IS IT THE SECOND ONE

OpenStudy (anonymous):

yes... it be that...:)

OpenStudy (maheshmeghwal9):

Answer is like that:- \[14x^2+47x+15\] \[14x^2+42x+5x+15\] \[14x(x+3)5(x+3)\] \[(14x+5)(x+3)\] I think now u can get it:)

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