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Mathematics 18 Online
OpenStudy (anonymous):

(tan theta +sec theta - 1)/(tan theta-sec theta +1)=sec theta +tan theta

OpenStudy (ajprincess):

is it 1/(tan theta + sec theta0 or 1/tan theta

OpenStudy (anonymous):

no 1/(tan theta +sec theta + 1)

OpenStudy (ajprincess):

using tan theta=sin theta/cos theta, sect theta= 1/cos theta, cos^2theta+sin^2theta I thnk u will b able to prov it.

OpenStudy (anonymous):

i am getting (sin theta +1 -cos theta)

OpenStudy (ajprincess):

that is for the upper part I suppose isn't it?

OpenStudy (anonymous):

yes

OpenStudy (ajprincess):

nw do the same for the lower part

OpenStudy (anonymous):

can u type

OpenStudy (ajprincess):

(sin theta +1 +cos theta)

OpenStudy (anonymous):

no lower one is (sin theta -1 +cos theta)

OpenStudy (anonymous):

sory it is (tan theta -sec theta +1) sorry sorry

OpenStudy (ajprincess):

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