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Mathematics 13 Online
OpenStudy (eyust707):

Abbies Question

OpenStudy (eyust707):

1/sin^2(x) + Sec^2(x)/Tan^2(x)

OpenStudy (eyust707):

so the trick here is that you can change the sec and tan into sin and cos

OpenStudy (eyust707):

secx = 1/cosx tanx = sinx/cosx

OpenStudy (eyust707):

so that means that

OpenStudy (eyust707):

sec2x = 1/cos2x tan2x = sin2x/cos2x

OpenStudy (eyust707):

do you get that so far?

OpenStudy (eyust707):

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