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3 particles,each of mass M are situated at the vertices of an equilateral triangle of the side a.The only forces acting on the particles are their mutual gravitational forces.It is desired that each particle move in a circle,while maintaining the original mutual separation a.Then the initial velocity that should be given to each particle is
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|dw:1339089583956:dw| Each of these particles will apply force \(2F_g*\cos30\) So, \( \frac{mv^2}{r} = 2F_g*\cos 30 \)
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