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10. Joe has a collection of nickels and dimes that is worth $2.10. If the number of dimes was tripled and the number of nickels was increased by 24, the value of the coins would be $5.70. How many nickels and dimes does he have?
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5n+10d=210 5(n+24)+10(3d)=570 -->5n+120+30d=570 -->5n+30d=450 So set up a system: 5n +10d = 210 -5n - 30d =-450 ----------------- 0n -20d=-240 d=12 -->5n+10(12)=210 --> 5n+120=210 -->5n=90 --> n=18 Final Answer: 12 dimes, 18 nickels.
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