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OpenStudy (anonymous):
y'=
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
y'=y^(2)
OpenStudy (anonymous):
y'=y2 this is indicated as y prime..... therefore, y'= primes y2.....
OpenStudy (anonymous):
What can you conclude about the solution of y'=y^(2) just by looking
OpenStudy (anonymous):
can you also help me the following? verify that y=-1/(x+c) are solution y'=y^(2). Find solution to the equation with the initial condition y(0)=1/3
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