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Mathematics 8 Online
OpenStudy (anonymous):

y'=

OpenStudy (anonymous):

?

OpenStudy (anonymous):

y'=y^(2)

OpenStudy (anonymous):

y'=y2 this is indicated as y prime..... therefore, y'= primes y2.....

OpenStudy (anonymous):

What can you conclude about the solution of y'=y^(2) just by looking

OpenStudy (anonymous):

can you also help me the following? verify that y=-1/(x+c) are solution y'=y^(2). Find solution to the equation with the initial condition y(0)=1/3

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