Question

The difference of the squares of two consecutive odd integers is 48. Find the integers.

Answer 1

x^2-y^2=48
x-y=2

solve this system.

Answer 2

how do you solve that? Sorry, I don't find anything in common in order to solve it

Answer 3

solve for y in the second equation: y=x-2
substitute that into the first equation: x^2 - (x-2)^2 = 48

Answer 4

now solve that equation involving only x...:)

Answer 5

Does the negative distribute? @dpaInc

Answer 6

no.. do the exponentiation first .... expand (x-2)^2 to (x^2-4x+4)

Answer 7

And so then it becomes -x^2+4x-4?
@dpaInc

Answer 8

yes...

Answer 9

notice the x^2 cancel

Answer 10

Yup! :) Thank you

Answer 11

yw..:)