Question

PLEASE HELP WITH THIS VECTORS PROBLEM!



The points P(-2 , 1), Q(-6 , 4), R(4 , 3), S(8 , 0) are four vertices of parallelogram PQRS.

a) Find the measures of internal angles of the parallelogram, to the nearest degree.

b) Find the measures of the angle between diagonals of the parallelogram to the nearest degree.

Please show all work, thanks (:

Answer 1

PQ=(-6-(-2),4-1)=(-4,3)
QR=(10,-1)
angle between this sides is = arccos (PQ . QR/|PQ||QR|)=arccos (-40-3/5*sqrt101)
( "." stands for dot product)
do the same for the rest