Question

PLEASE HELP WITH THIS VECTORS PROBLEM!



The points P(-2 , 1), Q(-6 , 4), R(4 , 3), S(8 , 0) are four vertices of parallelogram PQRS.

a) Find the measures of internal angles of the parallelogram, to the nearest degree.

b) Find the measures of the angle between diagonals of the parallelogram to the nearest degree.

Please show all work, thanks (:

Answer 1

Is this right?

\[SP=[-10 , 1]\]
\[SR=[-4 , 3]\]
\[(a)(b)=|a||b|\cos \Theta\]
\[[-10 , 1] [-4 , 3] = (\sqrt101)5\cos \Theta \]
\[40+3=5\sqrt101\cos\]
\[43/5\sqrt101=\cos \Theta\]
\[\Theta=\cos ^{-1} (43/5\sqrt101)\]
\[\Theta=31.16\]

Answer 2

yes

Answer 3

Ok, thanks So angle S and Q is 31.16 and angle P and R is 58.84 right?