A company builds computers. It costs $7,600 to build 10 computers and $12,200 to build 20 computers. Which equation models the cost, C(x), as a linear function of the number of computers built, x?

C(x) = 460x − 3000

C(x) = 3000x − 460

C(x) = 460x + 3000

C(x) = 3000x + 460

Question

A company builds computers. It costs $7,600 to build 10 computers and $12,200 to build 20 computers. Which equation models the cost, C(x), as a linear function of the number of computers built, x?

C(x) = 460x − 3000

C(x) = 3000x − 460

C(x) = 460x + 3000

C(x) = 3000x + 460

pfenn1 · Answer

Let x = number of computers built, A = a constant, B = unit cost to build a computer.  $$7600=A+10B$$$$12200=A+20B$$

pfenn1 · Answer

You have two equations and two unknowns.  Do you know how to solve for A and B?