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81^3/4
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|dw:1339125114559:dw|
simplify...
\[81^{3/4}=81\times81^{-1/4}\]\[=81\times\frac{1}{\sqrt[4]{81}}\]\[=81\times\frac{1}{\sqrt[4]{3^4}}\]\[=81\times\frac 13\]\[=\cdots\]
or simply \[81^{3/4}=({3^4})^{3/4}=3^3=\cdots\]
wait thats not right... 3^2 is 9... which is the square root of 81.. which is not right...
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Always remember that for these, if you can find the root first, do it first.|dw:1339125853823:dw|
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