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f(x)=3(x-1)^2 vertex? line of symmetry? graph
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Line of symmetry looks like x = k, when k is a constant, and the x value of the vertex.
Vertex is there -> f(x) = a(x-h)+k (h,k)
its an order pair (numbers)
Vertex is (1, 0). Axis of symmetry is x = 1
|dw:1339127325225:dw| would the graph be like this....roughly?
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