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What is the solution to the equation 3^1-2x = 2?
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\[3^{1-2 x}=2\]
\[\begin{array}{l} 3^{1-2 x}=2 \\ \text{take the log to the base }3\text{ of both sides and rearrange it} \\ 1-2 x=\frac{\log (2)}{\log (3)} \\ \text{Subtract }1\text{ from both sides} \\ -2 x=\frac{\log (2)-\log (3)}{\log (3)} \\ \text{divide both sides by }-2 \\ x=-\frac{\log (2)-\log (3)}{2 \log (3)} \\\end{array}\]
The options are: -0.292 -0.185 0.185 0.292
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you need it to calculate decimal solutions. 0.185
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