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Mathematics 17 Online
OpenStudy (anonymous):

f(x)=1/2(x+1)^2+6 vertex? line of symmetry? max/min of f(x)?

sam (.sam.):

1/2(x+1)^2+6 is in the completing the square form

sam (.sam.):

so, vertex is (-1,6)

sam (.sam.):

symmetry at x=-1

sam (.sam.):

It should be a minimum point since coefficient of x^2 is positive

OpenStudy (anonymous):

|dw:1339133646080:dw| would the graph look like this....roughly?

sam (.sam.):

no, a minimum graph is |dw:1339133722422:dw|

sam (.sam.):

the one you drawn is maximum graph

OpenStudy (anonymous):

ok ty

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