Question

The last digit of 7^243 * 9^457 is?

Answer 1

@Arnab09 @experimentX

Answer 2

7^1 ->last number 7
7^2 -> last number 9
7^3 -> last number 3

therefore since 243 is a multiple of 3 last digit of 7^ 243 is 3

Answer 3

yeah, 3^^

Answer 4

now for 9

9^1 -> last number 9

9^2 -> last number 1

9^3 -> last number 9

therefore all odd numbers have 9 at end...457 is odd so last digit is 9

Answer 5

9 x 3 = 27//so 7 is the last digit

Answer 6

in this case, 7^n..the last term will be 7, 9, 3, 1... and repeat
9^n..... 9,1..... and repeat

Answer 7

@lgbasallote u r correct thxx