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OpenStudy (anonymous):
Explain how to use the graph of f(x) = 2x to obtain the graph of g(x) = log2x.
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OpenStudy (apoorvk):
well, do you really that g(x) = log(f(x))?
OpenStudy (anonymous):
yea
OpenStudy (apoorvk):
Now, now y=2x is a graph that is steeper than y=x. means, y increases more rapidly in this case. so if the argument of log (i.e. '2x') increases faster, the graph of log2x moves like: |dw:1339161872677:dw|
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