Question

The line of symmetry of the parabola whose equation is y = ax2 - 4x + 3 is x = -2. What is the value of "a"?
Step by step please

Answer 1

You know completing the square?

Answer 2

Kind of

Answer 3

\[ax^2 - 4x + 3\]
\[a(x^2-\frac{4x}{a})+3\]
\[a(x-\frac{2}{a})^2-(\frac{4x^2}{a^2})(a)+3\]
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\[x=\frac{2}{a}\]
a should be -1