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What are the foci of the graph x^2-4y^2=16
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\[ \frac{x^2}{4^2}-\frac{y^2}{2^2}=1 \]
yes
a=4 b=2 c^2= a^2 + b^2 = 20
\[ c= 2 \sqrt{5} \]
Elias, my son. You are a very thorough educator. I have learnt that you have been educating for 40 years.
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The foci are (c,0) and (-c,0)
I cannot be as good as Sir Isaac Newton !!!!
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