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Find the excluded value of x for the polynomial expression: . x-8/8x+1 8 -8 1/8 -1/8
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why would we need to exclude any value?
idk
ok, tell me then; what is 5/0 ?
if we try to solve that we get: 5/0 = n 5 = 0*n ; how could we possibly work that out?
i dont kno thats y i need help
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this is the help
dividing by zero is a mathical nono. so, we need to exclude anything that would make the denominator equal to zero
when does: 8x-1 = 0 ?
err, 8x + 1 = 0 that is
when its a negative
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good start, x would have to be a negative number at least
you have two negatives to choose from; if anything you can plug them in to see what fits
so it would be -1/8
so it would be -1/8
-1/8 is correct :)
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