Question

Part 1: Solve each of the quadratic equations below. Show your work.

x^2 – 36 = 0 and x^2 = 8x – 12

Part 2: Describe what the solution(s) represent to the graph of each.

Part 3: How are the graphs alike? How are they different?

Answer 1

for x^2 -36 =0 can using formula a^2 -b^2 =(a-b)(a+b)
x^2 -8x +12=0 can be factorizing like (x-6)(x-2)=0

- so than can you continue ?

Answer 2

no im kinda lost..can you work me through it

Answer 3

x˘2 -36 =(x-6)(x+6)

ok ?

Answer 4

sorry there is x^2 -36 =(x-6)(x+6)

Answer 5

ok

Answer 6

so now can you getting the roots of these equations ?

Answer 7

im confused

Answer 8

(x-6)(x+6)=0 when this will be satisfied ?

Answer 9

so when x-6=0 and when x+6=0

yes ?

Answer 10

yes

Answer 11

but yoou know that x-6=0 so than x=6 and the same when x+6=0 so than x=-6

Answer 12

okay now what

Answer 13

youhave there again (x-6)(x-2)=0

can you solve it the same like the first ?

Answer 14

i got it thanks :)

Answer 15

ok

good luck

bye